Answer:
A. 10%
Step-by-step explanation:
Let events A nad B be:
A = an employee is a female
B = an employee is under the age of 30.
Use formula
[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex]
There are 200 employees, 150 of them are female, then
[tex]P(A)=\dfrac{150}{200}=\dfrac{3}{4}=0.75[/tex]
There are 200 employees, 40 of them are under the age of 30, then
[tex]P(B)=\dfrac{40}{200}=\dfrac{1}{5}=0.2[/tex]
The probability of randomly selecting an employee who is a female or under the age of 30 is 85%, then
[tex]P(A\cup B)=0.85[/tex]
Thus,
[tex]0.85=0.75+0.2-P(A\cap B)\\ \\0.85=0.95-P(A\cap B)\\ \\P(A\cap B)=0.95-0.85=0.1[/tex]
Therefore, the probability of randomly selecting an employee who is a female and under the age of 30 is 0.1 or 10%.
