Two planes are flying around the world. The first plane is flying at 300 miles per hour (mph) and is 350 miles ahead of the second plane. The second plane is flying at 400 mph. How long will it take for the second plane to catch the first plane?

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Answer:

It takes 3.5 hours for the second plane to catch the first plane.

Step-by-step explanation:

From the information given:

  • Rate of the first plane =  300 miles per hour
  • Rate of the second plane =  400 miles per hour
  • The first plane is 350 miles ahead of the second plane.

To find when the second plane catches the first plane, the distances of both planes must be equal.

We can use Distance = Rate x Time.

Let t be the time.

Distance of the first plane = Rate x Time = [tex]300\cdot t + 350[/tex]

Distance of the second plane = Rate x Time = [tex]400\cdot t [/tex]

Distance of the second plane = Distance of the first plane

[tex]400\cdot t=300\cdot t + 350[/tex]

Solving for t.

[tex]100\cdot t = 350[/tex]

t = 3.5 hours

It takes 3.5 hours for the second plane to catch the first plane.

The distance travelled by the two planes is an illustration of a linear function.

It will take the second plane 3.5 hours to catch up with the first plane

Let t represent time and d represent distance

The distance traveled by the first plane is represented as:

[tex]\mathbf{d_1 = 350 + 300t}[/tex]

The distance traveled by the second plane is represented as:

[tex]\mathbf{d_2 = 400t}[/tex]

Both planes will be at the same distance, when d1 = d2.

So, we have:

[tex]\mathbf{400t = 350 + 300t}[/tex]

Subtract 300t from both sides

[tex]\mathbf{400t - 300t = 350}[/tex]

Subtract

[tex]\mathbf{100t = 350}[/tex]

Divide both sides by 100

[tex]\mathbf{t = 3.50}[/tex]

Hence, it will take the second plane 3.5 hours to catch up with the first plane

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