Answer
given,
mass of crate = 32.5 Kg
horizontal force = 14 N
initial speed, u = 0 m/s
a) acceleration produced = ?
we know,
F = m a
[tex]a = \dfrac{F}{m}[/tex]
[tex]a = \dfrac{14}{32.5}[/tex]
a = 0.431 m/s²
b) using equation of motion
t = 10 s
[tex]s = ut + \dfrac{1}{2}at^2[/tex]
[tex]s = 0 + \dfrac{1}{2}\times 0.431\times 10^2[/tex]
s = 21.54 m
c) again using equation of motion
v = u + at
v = 0 + 0.431 x 10
v = 4.31 m/s
