Answer:
A) 0
Step-by-step explanation:
Given that
[tex]Q=x^{3}-x\\\\x(x^{2}-1)\\\\x(x+1)(x-1)[/tex]
Divisor = 6 = 3*2
[tex]\frac{Q}{D}=\frac{(x)(x+1)(x-1)}{6}\\\\\frac{Q}{D}=\frac{(x)(x+1)(x-1)}{2 \times 3}\\[/tex]
As it can be see that x ≥ 75 and Q is product of three consecutive terms (x-1), x, (x+1) which is always completely divisible by 2, 3 and 6. So remainder is zero
