Respuesta :
Answer:
The Dimension of new garden is [tex]25 \ feet\ \times 10\ feet.[/tex]
Step-by-step explanation:
Given:
Perimeter of new garden = 70 feet.
Let the length of the new garden be 'l'.
Also Let the width of the new garden be 'w'.
We need to find the dimension of new garden.
Now Given:
Length is 5 feet shorter than three times it width.
framing the equation we get;
[tex]l =3w-5 \ \ \ \ equation\ 1[/tex]
Now we know that;
Perimeter of rectangle is equal to twice the sum of length and width.
framing in equation form we get;
[tex]2(l+w)=70[/tex]
Now Diving both side by 2 using Division property of equality we get;
[tex]\frac{2(l+w)}2=\frac{70}{2}\\\\l+w =35[/tex]
Now Substituting equation 1 in above equation we get;
[tex]3w-5+w=35\\\\4w-5=35[/tex]
Adding both side by 5 Using Addition Property of equality we get'
[tex]4w-5+5=35+5\\\\4w=40[/tex]
Now Diving both side by 4 using Division property of equality we get;
[tex]\frac{4w}{4}=\frac{40}{4}\\\\w=10\ ft[/tex]
Now Substituting the value of 'w' in equation 1 we get;
[tex]l =3w-5\\\\l =3\times10-5\\\\l = 30-5\\\\l= 25\ ft[/tex]
Hence The Dimension of new garden is [tex]25 \ feet\ \times 10\ feet.[/tex]
