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The orbital quantum number for the electron in a hydrogen atom is l=5. What is the smallest possible value (algebraically) for the total energy of this electron? Give your answer in electron volts.

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Answer:

0.378 eV

Explanation:

Energy of a level is given by

[tex]E_n=\dfrac{13.6}{n^2}\ eV[/tex]

where,

n = Principle quantum number

The maximum value for the orbital angular momentum is given by

(n-1)

Now, l = 5

So this means that n can be any integer greater than 5.

Hence, n = 6 (minimum energy)

[tex]E_6=\dfrac{13.6}{6^2}\ eV\\\Rightarrow E_6=0.378\ eV[/tex]

So, the total energy of this electron is 0.378 eV

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