Tabbyjack
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Which equation can be solved to find one of the missing side lengths in the triangle?
60
12 units
O cos(609) = 12
O cos(600) =
O COS(60°) = 6

Respuesta :

calculista

Answer:

[tex]cos(60^o)=\frac{a}{12}[/tex]

Step-by-step explanation:

The complete question in the attached figure

we know that

In the right triangle of the figure

The cosine of the angle of 60 degrees is equal to divide the adjacent side to the angle of 60 degrees (BC) by the hypotenuse (AB)

so

[tex]cos(60^o)=\frac{BC}{AB}[/tex]

we have

[tex]BC=a\ units\\AB=12\ units[/tex]

substitute the values

[tex]cos(60^o)=\frac{a}{12}[/tex]

Ver imagen calculista
abidemiokin

The correct equation that represents the side length is Cos 60 = a/12

Trigonometry identity

From the triangle given, we have the following

  • Adjacent = a
  • Hypotenuse = 12

Using the soh cah toa identity

Cos theta = adj/hyp

Cos 60 = a/12

Hence the correct equation that represents the side length is Cos 60 = a/12

Learn more on SOH CAH TOA here: https://brainly.com/question/20734777

Ver imagen abidemiokin

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