Answer:
[tex]\frac{15}{32}[/tex]
Step-by-step explanation:
Given that a coin is flipped 5 times. Let us assume it is a fair coin with probability for head or tail equally likely and hence 0.50
Sample space would have [tex]2^5 = 32[/tex] possibilities
For two heads never occurring in a row favourable outcomes are
HTTTT,HTTHT,HTTTH, HTHTH, HTHTT, THTHT, THTTT, THTTH, TTHTH, TTHTT, TTTHT, TTTTH, TTTTT, TTTTH
Hence probability =
Favorable outcomes/Total outcomes=
[tex]\frac{15}{32}[/tex]
