Answer:
a. 8.66 minutes
Step-by-step explanation:
Since the flight times are uniformly distributed, the standard deviation can be calculated as follows:
[tex]\sigma = \frac{b-a}{\sqrt{12}}[/tex]
Where 'b' is the maximum flight time (150 minutes) and 'a' is the minimum flight time (120 minutes):
[tex]\sigma = \frac{150-120}{\sqrt{12}}\\\sigma = 8.66\ minutes[/tex]
The distribution's standard deviation is 8.66 minutes.
