Answer:
Partial pressure of H₂ is 0.375 atm
Explanation:
We apply the mole fraction to solve this.
Standard pressure is 1 atm
Mole fraction of a gas = Moles of gas / Total moles
Mole fraction of pressure = Partial pressure of gas / Total pressure
Both values are the same
Total moles = 4 moles of O₂ + 3 moles of H₂ and 1 mol of N₂ = 8 moles
3 moles H₂ / 8 moles = Partial pressure H₂ / 1 atm
(3 / 8 ) .1 = 0.375 atm → Partial pressure of H₂
The partial pressure exerted by the hydrogen gas, H₂ in the container is 0.375 atm
We'll begin by calculating the mole fraction of H₂ in the gas mixture. this can be obtained as follow:
Mole of O₂ = 4 moles
Mole of H₂ = 3 moles
Mole of N₂ = 1 mole
Total mole = 4 + 3 + 1 = 8 moles
[tex]mole \: fraction \: = \frac{mole \: of \: gas}{total \: mole} \\ \\ = \frac{3}{8} \\ \\ [/tex]
Mole fraction of H₂ = 0.375
Total pressure = STP = 1 atm
Partial pressure = mole fraction × Total Pressure
Partial pressure of H₂ = 0.375 × 1
Therefore, the partial pressure of H₂ in the container is 0.375 atm
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