Answer:
A) 36 g
Explanation:
From the source, some values have been correct.
Given that;-
Mass of NaCl formed = 116 grams
Molar mass of NaCl = 58 g/mol
Moles of NaCl = [tex]\frac{Mass}{Molar\ mass}=\frac{116}{58}\ mol=2\ mol[/tex]
According to the reaction shown below:-
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
1 mole of NaCl and 1 mole of [tex]H_2O[/tex] are produced upon reaction.
So,
2 moles of NaCl and 2 moles of [tex]H_2O[/tex] are produced upon reaction.
Moles of water = 2 moles
Molar mass of water = 18 g/mol
Mass = [tex]Moles\times Molar\ mass=2\times 18\ g=36\ g[/tex]
36 g of [tex]H_2O[/tex] is produced.
