Bert didn't finish 1/8 of the problems on a math test he made Mistakes on 1/6 of the problems the rest he answered correctly what fraction of the problems did he answer correctly

Respuesta :

Answer:

The fraction of the problems did he answer correctly is [tex](\frac{35}{48})[/tex]

Step-by-step explanation:

Here, let us assume the total number of problems in the test = p

Now, Bert did not finish 1/8 of the problems.

⇒The number of unfinished problems by Bert  = [tex]\frac{1}{8}  \times p= \frac{p}{8}[/tex]

Also, the number of finished problems  

=  Total problems - Unfinished problems

[tex]= p - \frac{p}{8}  = \frac{7p}{8}[/tex]

Now, again 1/6 of the total finished problems had mistakes.

So, the number of problems with mistakes = [tex]\frac{1}{6}  \times \frac{7p}{8}   = \frac{7p}{48}[/tex]

The total answers did correctly

= Total answers done - Problem with mistakes

[tex]= \frac{7p}{8} - \frac{7p}{48}  = \frac{(42 - 7)p}{48}   = \frac{35}{48}p[/tex]

Hence, the fraction of the problems did he answer correctly is [tex](\frac{35}{48})[/tex]