Answer:
b. 85
Step-by-step explanation:
Average grade (μ) = 75
Standard deviation (σ) = 8
Assuming a normal distribution, the z-score corresponding to the upper 10% of the test grades is z = 1.28.
The minimum grade 'X' within the top 10% is given by:
[tex]z=\frac{X-\mu}{\sigma}\\1.28=\frac{X-75}{8}\\X=85.24[/tex]
Rounding to the nearest percent, the dividing point between an A and a B grade is 85.