For this case we have to:
w: Represents the width of the rectangle
L: Represents the length of the rectangle
Then, the perimeter is given by:
[tex]P = 2w+2L[/tex]
According to the statement we have:
[tex]L = 3.5+w\\P = 58[/tex]
Substituting we obtain the given equation:
[tex]2w+2 (3.5 +w) = 58\\2w+7+2w = 58\\4w+7 = 58\\4w = 58-7\\4w = 51\\w = \frac {51} {4}\\w = 12.75[/tex]
Thus, the width of the rectangle is 12.75 feet
Answer:
The width of the rectangle is 12.75 feet
