A business organization needs to make up a 6 member fund-raising committee. The organization has 10 accounting majors and 7 finance majors. In how many ways can the fund-raising committee be formed if at most 2 accounting majors are on the committee?

Respuesta :

Answer:

Total number of ways will be 1855

Step-by-step explanation:

It id given that business organization needs to make a 6 member fund rising committee.

It is given there are 10 accounting majors and 7 finance majors

So total = 10+7 = 17

It is given that there are at most 2 accounting majors

So there can 0 ,1 and 2 accounting majors

So number ways will be equal to [tex]^{10}C_0\times ^7C_6+^{10}C_1\times ^7C_5+^{10}C_2\times ^7C_4=10\times 7+10\times 21+\times 45\times 35=1855[/tex]

So total number of ways will be 1855

There are 1792 ways the fund-raising committee can be formed if at most 2 accounting majors are on the committee

The given parameters are:

Members to select  = 6

Accounting majors = 10

Finance majors = 7

To select at most 2 accounting majors, then the following must be true

(Accounting, Finance) = (0,6) (1,5) (2,4)

So, the number of ways of selecting the committee members is:

[tex]n = ^{10}C_0 * ^{7}C_6 + ^{10}C_1 * ^{7}C_5 + ^{10}C_2 * ^{7}C_4[/tex]

Evaluate the combination expressions

[tex]n = 1 * 7 + 10 * 21 + 45 * 35[/tex]

Evaluate

[tex]n = 1792[/tex]

Hence, there are 1792 ways the fund-raising committee can be formed if at most 2 accounting majors are on the committee

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