Answer:
225000J
Step-by-step explanation:
[tex]W=F \times S.............1[/tex]
where
W= work done
F=force
S=distance
but F=ma
so we can write the equation
[tex]F=m \frac{(v - u)}{t} .........2[/tex]
Also,
[tex]S = ( \frac{u + v}{2})t...........3[/tex]
We put equation (2) and equation (3) into equation (1)
This implies,
[tex]W =m\frac{(v - u)}{t} \times ( \frac{u + v}{2})t[/tex]
[tex]W =m(v - u)\times ( \frac{u + v}{2})[/tex]
From the question
m=6000kg
u=5m/s
v=10m/s
By substitution we obtain
[tex]W =6000(10 - 5)\times ( \frac{5 + 10}{2})[/tex]
[tex]W =3000 \times 5\times15[/tex]
[tex]W=225000J[/tex]
