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What set of transformations are applied to parallelogram ABCD to create A″B″C″D″?
'Parallelogram formed by ordered pairs A at negative 4, 1, B at negative 3, 2, C at negative 1, 2, D at negative 2, 1. Second parallelogram transformed formed by ordered pairs A double prime at 1, negative 4, B double prime at 2, negative 3, C double prime at 2, negative 1, D double prime 1, negative 2.

Respuesta :

Answer:

(1) it's a counterclockwise 90° and then reflection over Y axis transformation

(2) or just reflection across y = x

Step-by-step explanation:

A   (-4 , 1)     B  (-3 , 2)    C  (-1 , 2)    D  (-2, 1)

A'' (1 , -4)     B'' (2 , -3)    C'' (2 , -1)   D'' (1, -2)

First step: 90 degree rotation counterclockwise around the origin

(x, y) ->  (-y, x)

A'  (-1 , -4)     B' (-2 , -3)    C' (-2 , -1)    D' (-1, -2)

2nd step: reflection across Y axis, negate the value of the x-coordinate of each point, but leave the y value the same

(x, y) -> (-x, y)

A'' (1 , -4)     B'' (2 , -3)    C'' (2 , -1)   D'' (1, -2)

2nd resolution: Reflection across y = x

(x, y) -> (y, x)

A   (-4 , 1)     B  (-3 , 2)    C  (-1 , 2)    D  (-2, 1)

A'' (1 , -4)     B'' (2 , -3)    C'' (2 , -1)   D'' (1, -2)

Ver imagen kenlingdad
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Answer: Reflected over the X axis and rotated 90° counterclockwise

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