Answer:
Explanation:
Given
Time taken to reach ground is [tex]t=2.7\ s[/tex]
Malda initial velocity [tex]u=95\ cm/s[/tex]
Let h be the height of Cliff
using [tex]h=ut+\frac{1}{2}at^2[/tex]
where, u=initial velocity
t=time
In first case chirpy drop downward thus u=0
[tex]h=0+\frac{1}{2}(9.8)(2.7)^2[/tex]
[tex]h=35.72\ m[/tex]
For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]
time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by
[tex]R=u\times t[/tex]
[tex]R=0.95\times 2.7=2.43\ m[/tex]
