For this case we must solve the following expression:
[tex]8- \frac {5} {6}[/tex] ÷ [tex]\frac {7} {8}[/tex]
According to the PEMDAS algebraic order method, we have the following order:
P: Parenthesis
E: Exponents
MD: Multiplication and division
AS: Addition and subtraction
So, we have:
[tex]8- \frac {\frac {5} {6}} {\frac {7} {8}} =\\8- \frac {5 * 8} {6 * 7} =\\8- \frac {40} {42} =\\8- \frac {20} {21} =[/tex]
[tex]\frac {8 * 21-20} {21} =\\\frac {168-20} {21} =\\\frac {148} {21} =\\7 \frac {1} {21}[/tex]
Answer:
[tex]7 \frac {1} {21}[/tex]
