Respuesta :
Answer:
4 moles, 160 g
Explanation:
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
For [tex]H_2SO_4[/tex]:-
Mass of [tex]H_2SO_4[/tex] = 196 g
Molar mass of [tex]H_2SO_4[/tex] = 98 g/mol
The formula for the calculation of moles is shown below:
[tex]moles = \frac{Mass\ taken}{Molar\ mass}[/tex]
Thus,
[tex]Moles= \frac{196\ g}{98\ g/mol}[/tex]
[tex]Moles\ of\ Sulfuric\ acid= 2\ mol[/tex]
According to the given reaction:
[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]
1 mole of sulfuric acid reacts with 2 moles of NaOH
So,
2 moles of sulfuric acid reacts with 2*2 moles of NaOH
Moles of NaOH must react = 4 moles
Molar mass of NaOH = 40 g/mol
Mass = Moles*molar mass = [tex]4\times 40\ g[/tex] = 160 g
