Answer
given,
Radius of circular turn (r)= 2200 km = 2200 x 10³ m
speed of the spaceship = 27800 km/h
v = 27800 x 0.278
v = 7728.4 m/s
a) magnitude of angular velocity
we know,
v = r ω
[tex]\omega = \dfrac{v}{r}[/tex]
[tex]\omega = \dfrac{7728.4}{2200 \times 10^3}[/tex]
ω = 3.51 x 10⁻³ rad/s
b) magnitude of radial acceleration
[tex]a_r = \dfrac{v^2}{r}[/tex]
[tex]a_r = \dfrac{7728.4^2}{2200 \times 10^3}[/tex]
a_r = 27.149 rad/s²
c) spaceship is moving with constant velocity, the tangential acceleration of the spaceship is equal to zero.
a_t = 0 m/s²
