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Calculate the frequency of homozygotes for an allele at a locus in a population at Hardy–Weinberg equilibrium if the frequency of the allele is 0.15. One other allele is present in this population.

Respuesta :

Answer:

0.0225

Explanation:

According to the given information, the gene under study has two alleles. The frequency of one allele is 0.15. The locus is at Hardy–Weinberg equilibrium. This means that the sum of the frequencies of two alleles would be one. The frequency of homozygotes for an allele in the population is calculated as the square of the frequency of that allele.  

Therefore, if the frequency of one allele in the population is = 0.15. Frequency of homozygotes for this allele in the population would be = 0.15 x 0.15 = 0.0225

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