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Light passes from substance A into substance B as shown. What could these two substances be?
A. A could be water (speed of light = 225,000 km/s); B could be air (speed of light = 300,000 km/s).
B. A could be ruby (speed of light = 170,000 km/s); B could be sapphire (speed of light = 170,000 km/s).
C. A could be ruby (speed of light = 170,000 km/s); B could be diamond (speed of light = 120,000 km/s).
D. A could be diamond (speed of light = 120,000 km/s); B could be water (speed of light = 225,000 km/s).

will mark as brainliest if correct Light passes from substance A into substance B as shown What could these two substances be A A could be water speed of light class=

Respuesta :

C. A could be ruby (speed of light = 170,000 km/s); B could be diamond (speed of light = 120,000 km/s).

Explanation:

Refraction is a phenomenon that occurs when a light rays crosses the boundary between two different mediums.

When this occurs, the light wave changes speed and also direction, according to Snell's law:

[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex] (1)

where

[tex]n_1[/tex] is the index of refraction of the first medium

[tex]n_2[/tex] is the index of refraction of the second medium

[tex]\theta_1[/tex] is the angle of incidence (the angle between the incident ray and the normal to the boundary)

[tex]\theta_2[/tex] is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

The index of refraction is the ratio between the speed of light in a vacuum (c) and the speed of light in the medium (v):

[tex]n=\frac{c}{v}[/tex]

Using this definition, we can rewrite eq.(1) as

[tex]\frac{\sin \theta_2}{\sin \theta_1} = \frac{v_2}{v_1}[/tex]

Where [tex]v_2[/tex] is the speed of light in the 2nd medium and [tex]v_1[/tex] the speed of light in the 1st medium.

Now let's analyze the situation represented in the figure: we see that as the light ray enters the 2nd medium, it bends towards the normal, this means that the angle of refraction is smaller than the angle of incidence:

[tex]\theta_2 < \theta_1[/tex]

This means that

[tex]\frac{\sin \theta_2}{\sin \theta_1}<1[/tex]

And therefore,

[tex]\frac{v_2}{v_1}<1[/tex]

So, the speed of light in the second medium is smaller than the speed of light in the first medium: this occurs only in option C), which is therefore the correct choice.

Learn more about refraction:

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