The solution is: x= 7 and y = 2
Step-by-step explanation:
Given equations are:
[tex]x = 3y+1\ \ \ \ Eqn\ 1\\x+4y = 15\ \ \ \ Eqn\ 2[/tex]
Putting x = 3y+1 in equation 2 from equation 1
[tex]3y+1+4y = 15\\7y+1 = 15\\[/tex]
Subtracting 1 from both sides
[tex]7y+1-1 = 15-1\\7y = 14[/tex]
Dividing both sides by 7
[tex]\frac{7y}{7} =\frac{14}{7}\\y = 2[/tex]
Putting y=2 in equation 1
[tex]x = 3(2) +1\\x = 6+1\\x = 7[/tex]
Hence,
The solution is: x= 7 and y = 2
Keywords: Linear equations, substitution method
Learn more about linear equations at:
- brainly.com/question/4706270
- brainly.com/question/4710621
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