Answer:
P₀ = 5.76 x 10⁻² MW
Explanation:
given,
efficiency of the power plant = 32%
Power produced by the nuclear fission = 0.18 MW
the power plant output = ?
using formula of efficiency
[tex]\eta = \dfrac{P_0}{P}[/tex]
where P is the power produced in the power plant
P₀ is the power output of the power plant
[tex]\eta = \dfrac{P_0}{P}[/tex]
[tex]0.32 = \dfrac{P_0}{0.18}[/tex]
P₀ = 0.18 x 0.32
P₀ = 0.0576 MW
P₀ = 5.76 x 10⁻² MW
Power plant output is equal to P₀ = 5.76 x 10⁻² MW
