Answer:
Option B.
Step-by-step explanation:
A solid straight line passes through (0, -1) and (3, 0)
Slope of the line = [tex]\frac{y-y'}{x-x'}[/tex]
= [tex]\frac{0+1}{3-0}[/tex]
= [tex]\frac{1}{3}[/tex]
Equation of the line passing through (0, -1) will be
y - y' = m(x - x')
[tex]y+1=\frac{1}{3}(x-0)[/tex]
[tex]y=\frac{1}{3}x-1[/tex]
Since this line is solid then there will the sign of (≥ or ≤)
If everything above and to the left of the line is shaded then the inequality will be
[tex]y\geq \frac{1}{3}x-1[/tex]
Therefore, the answer will be option B. [tex]y\geq \frac{1}{3}x-1[/tex]
