Respuesta :
Answer:
52 %
Explanation:
The tank is filled to one quarter its capacity
tank capacity filled with mixture = 1/4 × 24 gallons = 6 gallons
percentage of water in the mixture = 100 - 40 = 60%
60 % of 6 gallons = 3.6 gallon of water present
after two hours
the amount lost to evaporation = 0.5 gallons × 2 = 1 gallon
quantity of water remaining = 3.6 - 1 = 2.6 gallon
quantity of the mixture remaining after 1 gallon of water has been removed = 6 - 1 = 5 gallons
the concentration of water in the mixture in percentage =2.6 / 5 × 100 = 52 %
Answer: C = 52%
Therefore, the final concentration of the mixture is 52%
Explanation:
Given;
The total capacity of the tank = 24 gallons
Rate of evaporation of water r = 0.5 gallons/hour
Time of evaporation t = 2 hours
Initial Volume of mixture in the tank V = 1/4 × 24 = 6 gallons
Initial concentration of the mixture = 40%
Volume of sodium chloride in the mixture will be given as m.
m = 40% V = 40% of 6 = 2.4 gallons
Due to the evaporation the volume of the mixture would have reduced by to V'
V' = V - rt
V' = 6 - 0.5×2
V' = 5 gallons
Since the volume of sodium chloride in the mixture is not affected by the evaporation, m remain 2.4 gallons
the final concentration of water is
C = mass/volume
C = (5.0 - 2.4)/5
C = 2.6/5
C = 52%
Therefore, the final concentration of the mixture is 52%
