For this case we have the following system of equations:
[tex]-16x + 2y = -2\\y = 8x-1[/tex]
To solve, we substitute the second equation in the first:
[tex]-16x + 2 (8x-1) = - 2[/tex]
We apply distributive property to the terms within parentheses:
[tex]-16x + 16x-2 = -2\\-2 = -2[/tex]
Equality is met, so for any value of x it will be fulfilled. Therefore, the system of equations has infinite solutions.
Answer:
Infinite solutions
