Answer:
a) it has been shown
b) P(lose) = 0.62, P(win) = 0.38
c) P(lose) = 0.83, P(win) = 0.17
d) P(lose) = 0.96, P(win) = 0.04
Step-by-step explanation:
a) Since [tex]\frac{a}{b} =\frac{P(W_c)}{1-P(W_c)}[/tex]
Then by cross-multiplication,
[tex]a(1-P(W_c))=bP(W_c)\\a-aP(W_c)=bP(W_c)\\a=bP(W_c)+aP(W_c)=(a+b)P(W_c)[/tex]
So, [tex]P(W_c)=\frac{a}{a+b}[/tex]
b) P(lose) = 8/(8+5) = 8/13 = 0.62
P(win) = 5/(8+5) = 5/13 = 0.38
c) P(lose) = 5/(5+1) = 5/6 = 0.83
P(win) = 1/(5+1) = 1/6 = 0.17
d) P(lose) = 26/(26+1) = 26/27 = 0.96
P(win) = 1/(26+1) = 1/27 = 0.04