Answer:
Therefore,
AD = 7 unit
AE = 600 unit
EF = 30 unit
FB = 5 unit
Ar(EFGH)= 210 unit²
Ar(ABCD)= 4445 unit²
Step-by-step explanation:
Given:
Consider a rectangle ABCD as shown in the figure below where,
Area (ABCD) = 635 × 7 = 4445
Therefore length and width of a rectangle will be
LENGTH =635 = AB
WIDTH = 7 = AD
To Find:
AE =?
EF = ?
FB = ?
Ar(EFGH)=?
Ar(ABCD) =?
Solution:
We know that area of the rectangle is given by
[tex]\textrm{Area of rectangle}= LENGTH\times WIDTH[/tex]
[tex]\textrm{Area of rectangle ABCD}= 635\times 7=4445\ unit^{2}[/tex]
Substituting the values we get
[tex]\textrm{Area of rectangle AEHD}= AE\times 7\\\\4200=AE\times 7\\\therefore AE=\dfrac{4200}{7}=600[/tex]
Similarly for area rectangle FBCG,
[tex]\textrm{Area of rectangle FBCG}= FB\times 7\\\\35=FB\times 7\\\therefore FB=\dfrac{35}{7}=5[/tex]
Now we have
AB = 635,
[tex]AE + EF + FB = 635\\\\600+EF+5=635\\\\EF=635 -605=30\\\therefore EF = 30[/tex]
Similarly for area rectangle EFGH,
[tex]\textrm{Area of rectangle EFGH}= EF\times 7\\\\=30\times 7=210\ isunit^{2}[/tex]
Therefore,
AD = 7 unit
AE = 600 unit
EF = 30 unit
FB = 5 unit
Ar(EFGH)= 210 unit²
Ar(ABCD)= 4445 unit²
