Answer:
Question 2 ⇒ 95 calories
Question 3 ⇒ 40,933 logins
Step-by-step explanation:
Question 2.
Given:
The given equation is
[tex]y=30x+5[/tex]-----------------------(1)
Where x = number of laps
And y = calories burned
The student walked 3 laps.
The calories would be burn after they walked 3 laps, so we substitute [tex]x = 3[/tex] in equation 1.
[tex]y=30\times 3+5[/tex]
[tex]y=90+5[/tex]
[tex]y=95[/tex]
Therefore 95 calories would be burn if walked 3 laps.
Question 3.
The given equation is
[tex]y=-1067x+58005[/tex]---------------------(1)
Where x = temperature
And y = number of logins
temperature is given, so we put x = 16 in equation 1.
[tex]y=-1067\times 16+58005[/tex]
[tex]y=-17072+58005[/tex]
[tex]y=40933[/tex]
Therefore the outside temperature is 16° after 40,933 logins.
