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A fair coin is tossed 29 times. In how many outcomes do at least 2 tails occur?

a. 536,870,476
b. 1
c. 536,870,883
d. 536,870,882
e. 406
f. None of the above

Respuesta :

pedrocarratore

Answer:

d. 536,870,882

Step-by-step explanation:

The number of outcomes in which at least 2 tails occur (N(t>1)) is given by the total number of possible outcomes (N) subtracted by the number of possibilities in which one or none tails occur.

For each throw, there are two possible outcomes. The total number of outcomes is:

[tex]N= 2^{29}\\N=536,870,912[/tex]

There is only one outcome where no tails occur, while there 29 outcomes in which only one tails occur (one for each toss).

Therefore, the number of outcomes in which at least 2 tails occur is:

[tex]N(t>1) = 536,870,912 - 29 -1\\N(t>1) = 536,870,882[/tex]

d. 536,870,882

abidemiokin

The number of outcomes if at least 2 tails occur for a fair coin tossed 29 times is 536,870,882: Option D is correct

Probability is the likelihood or chance that an event will occur.

The formula for calculating probability is expressed as:

Probability = Expected outcome/Total outcome

If a  fair coin is tossed 29 times, the total number of outcomes will be expressed as:

[tex]2^{29} =536,870,912[/tex]

If at least 2 tails occur, the expected outcome will be 29 times

Pr(at least 2 tails occur) = [tex]2^{29} - 29 - 1[/tex]

Pr(at least 2 tails occur) = [tex]536,870,912 - 30 = 536,870,882[/tex]

Hence the number of outcomes if at least 2 tails occur is 536,870,882

Learn more here: https://brainly.com/question/13604758

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