Respuesta :
Answer:
14.776 inches
Step-by-step explanation:
32 pound mass stretches the spring by 11 inches,
where F = ke where k is a constant and e is the extension
32/11 = k
k = 2.91
then 43 pound will stretch it by
f = ke
43 / 2.91 = e in inches
e = 14.776 inches
Answer:the spring would be stretched 14.8 inches.
Step-by-step explanation:
Hooke's Law says that the force exerted by the spring in a spring scale varies directly with the distance that the spring is stretched.
If the force is F and the distance that the spring is stretched is e, then
F is directly proportional to e
Introducing a proportionality constant, k it becomes.
F = ke
If a 32 pound mass suspended on a spring scale stretches the spring 11 inches, it means that
32 = k × 11
k = 32/11
The expression becomes
F = 32e/11
If a 43 pound mass spring is stretched, then,
43 = 32e/11
32e = 43 × 11 = 473
e = 473/32 = 14.8 inches
