Solution:
[tex]\boxed{\frac{2}{9}, \frac{16}{3}}[/tex]
We have the following system of linear equations in two variables:
[tex]\begin{array}{c}(1)\\(2)\end{array}\left\{ \begin{array}{c}x-6y=4\\18y=4\end{array}\right.[/tex]
Perhaps you wrote a wrong system because this actually has one solution. A system of linear equations in two variables has no solution when the lines are parallel, that is, when they have the same slope but different y-intercept. This is not the case, so we can find the solution as follows:
From (2):
[tex]y=\frac{4}{18} \\ \\ y=\frac{2}{9}[/tex]
So, substituting this y-value into (1):
[tex]x-6y=4 \\ \\ x-6(\frac{2}{9})=4 \\ \\ x=4+\frac{12}{9} \\ \\ x=\frac{16}{3}[/tex]
So the solution is the point:
[tex]\boxed{\frac{2}{9}, \frac{16}{3}}[/tex]
Graphing lines: https://brainly.com/question/13799715
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