Respuesta :
Answer:
Speed of passenger train=18+30=48 mph
Speed of freight train=30 mph
Step-by-step explanation:
Let x be the speed of freight train.
Speed of passenger train=x+18 mph
Time taken by freight train=1.5+2.5=4 hrs
Time taken by passenger train to overtake the freight train=2.5 hrs
Distance=[tex]Speed\times time[/tex]
By using this formula
Distance traveled by passenger train=2.5(x+18) miles
Distance traveled freight train=4x
According to question
[tex]2.5(x+18)=4x[/tex]
[tex]2.5 x+45=4x[/tex]
[tex]45=4x-2.5 x[/tex]
[tex]45=1.5 x[/tex]
[tex]x=\frac{45}{1.5}=30[/tex]
Speed of freight train=30 mph
Speed of passenger train=18+30=48 mph
Answer:
Step-by-step explanation:
At the point where the passenger train overtook the freight train, both trains must have travelled an equal distance.
Let x represent the speed of the freight train.
The passenger train is travelling 18 mph faster than the freight train. This means that the speed of the passenger train would be
x + 18
The passenger train leaves a depot 1.5 hours after a freight train leaves the same depot. if the passenger train overtakes the freight train in 2.5h, it means that total time taken by the passenger train is 2.5h and total time taken by the freight train is 2.5 + 1.5 = 4 hours.
Distance travelled = speed × time
Distance travelled by freight train = 4 × x = 4x
Distance travelled by passenger train = 2.5(x + 18) = 2.5x + 45
Since they travelled equal distances, then
4x = 2.5x + 45
4x - 2.5x = 45
1.5x = 45
x = 45/1.5 = 30
Therefore,
the speed of the freight train is 30 mph and
the speed of the passenger train is x + 18 = 30 + 18 = 48 mph
