Answer:
the net work done after starting from rest is = 2.4 × 10⁵ J
Explanation:
Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J), The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below
E = W = 1/2mv².......................... Equation 1
Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.
v² = u² + 2as ................................. Equation 2.
Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.
Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)
Substituting these values into equation 2
v² = 0² +2×1×30
v² = 60
v = √60
v = 7.75 m/s
Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s
Substituting these values into equation 1,
W = 1/2(8.0×10³)(7.75)²
W = (4.0×10³)(60)
W = 240 × 10³ J
W = 2.4 × 10⁵ J
Therefore the net work done after starting from rest is = 2.4 × 10⁵ J
The net work done by all forces on the plane as it accelerates upward is [tex]2.4 \times 10^5J[/tex]
Work is said to be done when the force applied to an object causes the object to move a distance. Mathematically;
Workdone = Force * distance
The network done by the forces is converted into kinetic energy of the plane. Hence;
W = KE = [tex]\frac{1}{2}mv^2[/tex]
Given the following parameters
mass of an object = 8000kg
acceleration = 1.0 m/s²
distance = 30.0m
Get the required velocity using the equation of motion
[tex]v^2=u^2+2gs\\v^2=0^2+2(1)(30)\\v^2=60\\v=7.75m/s[/tex]
Get the work done by all the forces
[tex]W=\frac{1}{2}mv^2\\W=\frac{1}{2}(8000)(7.75)^2\\W=4000\times 60\\W=240,000J\\W=2.4 \times 10^5J[/tex]
Hence the net work done by all forces on the plane as it accelerates upward is [tex]2.4 \times 10^5J[/tex]
Learn more here: https://brainly.com/question/20748827