Answer:
For given system of equations the values of x and y is x=1 and y=0
Step-by-step explanation:
Given system of equations are
[tex]5x-3y=5\hfill (1)[/tex]
[tex]-2x+4y=-2\hfill (2)[/tex]
Now to solve the given system of equations by using addition method
Multiply the equation(1) into 2 we get
[tex]10x-6y=10\hfill (3)[/tex]
Multiply the equation(2) into 5 we get
[tex]-10x+20y=-10\hfill (4)[/tex]
Now adding the equations (3) and (4)
[tex]10x-6y=10[/tex]
[tex]-10x+20y=-10[/tex]
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[tex]14y=0[/tex]
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[tex]y=\frac{0}{14}[/tex]
[tex]y=0[/tex]
Therefore y=0
Substitute y=0 in equation (1) we get
[tex]5x-3y=5[/tex]
[tex]5x-3(0)=5[/tex]
[tex]5x-0=5[/tex]
[tex]5x=5[/tex]
[tex]x=\frac{5}{5}[/tex]
[tex]x=1[/tex]
Therefore x=1
For given system of equations the values of x and y is x=1 and y=0
