A spinner has 8 equal sectors labeled from 1 to 8. The spinner is spun twice.

What is the probability of getting an even number on the first spin and another even number on the second spin?




7/8

5/16

3/16

1/4

Respuesta :

On your first spin the chance is 1/2. The same goes for your second spin, but the chance of getting two consecutive even numbers is 1/2 x 1/2.
So the answer is 1/4.

The probability of getting an even number on the first spin and another even number on the second spin is 1/4

How to determine the probability?

The number on the spinner is:

n = {1....8}

There are 4 even numbers from 1 to 8.

So, the probability of landing on an even number is:

P(First) = 4/8

P(Second) = 4/8

The required probability is then calculated using:

P = P(First) * P(Second)

So, we have:

P = 4/8 * 4/8

Evaluate

P = 1/4

Hence, the probability is 1/4

Read more about probability at:

https://brainly.com/question/251701

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