The equivalent spring constant is 2667 N/m
Explanation:
We can solve the problem by using Hooke's law, which states that:
[tex]F=kx[/tex]
where
F is the force applied to the rubber bands
k is the equivalent spring constant of the two rubber bands
x is their stretching
In this problem, we know that
F = 32 N is the force applied
x = 1.2 cm = 0.012 m is the stretching of the bands
Solving for k, we find the equivalent spring constant of the two rubber bands:
[tex]k=\frac{F}{x}=\frac{32}{0.012}=2667 N/m[/tex]
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