Respuesta :
Answer:
[tex]\frac{4}{5}[/tex]
Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)= [tex]\frac{13}{25} +\frac{11}{25} -\frac{4}{25}[/tex]
taking LCD as 25 to solve.
⇒P(a∪b)= [tex]\frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}[/tex]
∴ P(a∪b)= [tex]\frac{4}{5}[/tex]
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is [tex]\frac{4}{5}[/tex].
