adrian1030ho
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The length of the diagonal of a rectangle is 10cm. If the length is 2cm longer than its width, find the length and the width of the rectangle.​

Respuesta :

carysechong

Step-by-step explanation:

if you divide the rectangle into half, you'll see a right angled triangle and immediately recognise the use of Pythagoras theorem.

Substitute them into the formula

[tex] {a}^{2} + {b}^{2} = {c}^{2} [/tex]

x as a, x+2 as b and 10 as c

Ver imagen carysechong
Ver imagen carysechong

Answer:

Step-by-step explanation:

BD is the diagonal =10cm

Breadth=x

length =x+2

In triangle ABD

BD2=AB2+AD2

100=x2+(x+2)2

=x2+x2+4+4x

=2x2+4+4x

96=2x2+4x

x2+2x-48=0

x2+8x-6x-48=0

x(x+8)-6(x+6)=0

(x+8)(x-6)=0

x=-8,x=6

width=6cm

length=6+2=8 cm

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