contestada

A fish tank, in a shape of rectangular prism, measures
100 cm × 60 cm × 40 cm. The water level reached the
midpoint of the base (the 50 cm mark), when the tank
was tilted to rest on a 60 cm edge, as shown in the
diagram on the right. What would be the depth of the
water, if the tank is returned to its horizontal position
(resting on its 60 cm × 100 cm base)?

Respuesta :

calculista

Answer:

The deep of the water would be 20 cm

Step-by-step explanation:

step 1

Find the volume of the water

The volume of the water is equal to

[tex]V=LWH[/tex]

we have

[tex]L=60\ cm\\W=40\ cm\\H=50/ cm[/tex]

substitute

[tex]V=(60)(40)(50)[/tex]

[tex]V=120,000\ cm^3[/tex]

step 2

Find the deep of the water, if the tank is returned to its horizontal position

(resting on its 60 cm × 100 cm base)

Now we have

[tex]L=60\ cm\\W=100\ cm\\H=?\ cm[/tex]

[tex]V=120,000\ cm^3[/tex]

substitute the given values

[tex]120,000=(60)(100)H[/tex]

solve for H

[tex]H=120,000/6,000[/tex]

[tex]H=20\ cm[/tex]

therefore

The deep of the water would be 20 cm

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