Answer:
[tex]9\sqrt{2} [/tex]
Step-by-step explanation:
The given question is :
[tex]\sqrt{8} +3\sqrt{2} +\sqrt{32}[/tex]
8 = 4 * 2
32 = 16 * 2
[tex]\sqrt{8} =\sqrt{4*2} = 2\sqrt{2} \\\sqrt{32} =\sqrt{16*2} =4\sqrt{2}[/tex]
∴ [tex]\sqrt{8} +3\sqrt{2} +\sqrt{32}[/tex]
= [tex]2\sqrt{2} +3\sqrt{2} +4\sqrt{2} [/tex]
= [tex]9\sqrt{2} [/tex]
