Respuesta :
Answer:
Potassium Dichromate(K2Cr2O7) is oxidising agent and will oxidise Hydrogen sulfide(H2S) to Sulphur(S).
The orange color of Potassium dichromate is changed to green due formation of Chromium sulphate.
Explanation:
The balance chemical equation for the reaction is :
[tex]K_{2}Cr_{2}O_{7} + 3H_{2}S + 4H_{2}SO_{4}\rightarrow[/tex] [tex]Cr_{2}(SO_{4})_{3} + 3S + K_{2}SO_{4} +7H_{2}O[/tex]
K2Cr2O7 = It is the commonly used inorganic reagent used for its oxidizing properties .It is crystalline , bright orange coloured.
In this reaction it oxidise Hydrogen sulfide to sulfate .
Hydrogen Sulfide = It has Formula H2S . It is a colourless gas .
It is foul smelling and act as reducing agent .
In this reaction H2S reduces Potassium dichromate(Cr = +6) to Chromium Sulfate (Cr = +3)
