Answer:
[tex]Slope(EA)=Slope(AC)=\dfrac{2}{3}[/tex]....Equation is True
Slopes are EQUAL for
Hence, E-A-C is the same Line.
Step-by-step explanation:
Given:
The three points for the given line are
point E( x₁ , y₁) ≡ ( -6 ,-4)
point A( x₂ , y₂) ≡ (0 , 0) .....Origin
point C(x₃ , y₃ ) ≡ (3 , 2)
To Find:
Slope EA = ?
Slope AC = ?
Solution:
For Two point Slope is given as
[tex]Slope=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
Substituting the values we get
[tex]Slope(EA)=\dfrac{0--4}{0--6}=\dfrac{4}{6}=\dfrac{2}{3}[/tex]
Similarly For AC we have,
[tex]Slope(AC)=\dfrac{2-0}{3-0}=\dfrac{2}{3}[/tex]
Therefore,
[tex]Slope(EA)=Slope(AC)[/tex]....Equation is True
Slopes are EQUAL for
Hence, E-A-C is the same Line.
Answer:
2/3
....Equation is True
Slopes are EQUAL for
SAME Line
Hence, E-A-C is the same Line.
Step-by-step explanation:
