Jadah has 15 dimes and 2 quarters
Solution:
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
She has 17 coins altogether
number of dimes + number of quarters = 17
d + q = 17 ----- eqn 1
She has $2 worth of quarters and dimes in her pocket
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 2
[tex]d \times 0.10 + q \times 0.25 = 2[/tex]
0.1d + 0.25q = 2 ---- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 17 - q ------- eqn 3
Substitute eqn 3 in eqn 2
0.1(17 - q) + 0.25q = 2
1.7 - 0.1q + 0.25q = 2
0.15q = 0.3
From eqn 3,
d = 17 - q = 17 - 2 = 15
Thus she has 15 dimes and 2 quarters
