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the sun rotates once in 25.05 days. That is 601.2 hours. so the sun's rotational speed is 0.0017 rotations per hour. what is the tangential velocity of a sunspot if the spot is 6.955 x 10^5 km from thew center of the sun?


in the part: 10^5 it means 10 to the power of 5, its an exponent, but i dint know how to put it in

Respuesta :

Answer:

[tex]v=2019.09\ m.s^{-1}[/tex]

Explanation:

Given:

  • time taken by the sun to complete one revolution, [tex]t=601.2\ hr[/tex]
  • radial distance of the sunspot, [tex]r=6.955\times 10^8\ m.s^{-1}[/tex]

Therefore, angular speed of rotation of sun:

[tex]\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}[/tex]

Now the tangential velocity of the sunspot can be given by:

[tex]v=r.\omega[/tex]

[tex]v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}[/tex]

[tex]v=2019.09\ m.s^{-1}[/tex]

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