A 0.060-kg tennis ball, initially moving at a speed of 12 m/s, is struck by a racket causing it to rebound in the opposite direction at a speed of 18 m/s.

What is the change in momentum of the ball?
A) 0.72 kg·m/s

B) 0.36 kg·m/s

C) 1.1 kg·m/s

D) 1.8 kg·m/s

Respuesta :

The change in momentum of the ball is D) 1.8 kg m/s

Explanation:

The change in momentum of the ball is given by:

[tex]\Delta p = m(v-u)[/tex]

where

m is the mass of the ball

v is the final velocity

u is the initial velocity

In order to calculate the change in momentum correctly, we have to correctly take into account the sign of the velocity. Taking the final direction of the ball as positive direction, we have:

u = -12 m/s is the initial velocity

v = +18 m/s is the final velocity (it changes sign because the direction has changed)

m = 0.060 kg is the mass of the ball

Solving the equation, we find the change in momentum of the ball:

[tex]\Delta p = (0.060)(+18-(-12))=1.8 kg m/s[/tex]

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