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A circuit contains a capacitor and a resistor connected in series. Of the circuit's capacitive reactance measured 650 Ω and its resistance measures 1,200 Ω, what is the phase angle between circuit voltage and current?

Respuesta :

Answer:

Ф = 28.41°

Explanation:

Given that

Capacitive reactance ,Xc = 650 Ω

Resistance ,R= 1200 Ω

As we know that phase angel Ф given as

[tex]tan\phi =\dfrac{X_c}{R}[/tex]

Now by putting the values

[tex]tan\phi =\dfrac{X_c}{R}[/tex]

[tex]tan\phi =\dfrac{650}{1200}[/tex]

tanФ = 0.541

Now by taking inverse

[tex]\phi=tan^{-1}0.541[/tex]

We get

Ф = 28.41°

Therefore the answer will be 28.41°.

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