Answer:
y = 6
Step-by-step explanation:
[tex]\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16} \quad\text{given}\\\\\dfrac{-4(y+4)}{y^2-16}=\dfrac{5(y-4)}{y^2-16}-\dfrac{7y+8}{y^2-16} \quad\text{use common denominator}\\\\-4y-16=5y-20-7y-8 \quad\text{multiply by that denominator}\\\\12=2y \quad\text{add 4y+28}\\\\6=y \quad\text{divide by 2}[/tex]
